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X^2+196X-676=0
a = 1; b = 196; c = -676;
Δ = b2-4ac
Δ = 1962-4·1·(-676)
Δ = 41120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{41120}=\sqrt{16*2570}=\sqrt{16}*\sqrt{2570}=4\sqrt{2570}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(196)-4\sqrt{2570}}{2*1}=\frac{-196-4\sqrt{2570}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(196)+4\sqrt{2570}}{2*1}=\frac{-196+4\sqrt{2570}}{2} $
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